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6x^2-250x+2500=0
a = 6; b = -250; c = +2500;
Δ = b2-4ac
Δ = -2502-4·6·2500
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-250)-50}{2*6}=\frac{200}{12} =16+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-250)+50}{2*6}=\frac{300}{12} =25 $
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